Saturday 25 August 2012

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Total number of Network and Host in different class of IPs



Class 'A'
(1-126). (0-255).(0-255).(0-255)
Net ID         Host ID
Total No. of Network = 126
Total No. of Host in a Network = (256×256×256)-2 = 16777216-2 = 16777214
Total No. of Computers = 126×16777214 = 2113928964
Class 'B'
(128-191).(0-255).(0-255).(0-255)
Net ID                     Host ID
Total No. of Network = 64×256 = 16384
Total No. of Host in a Network = (256×256)-2 = 65536-2 = 65534
Total No. of Computers = 16384×65534 = 1073741824
Class 'C'
(192-223).(0-255).(0-255).(0-255)
Net ID                            Host ID
Total No. of Network = 32×256×256 = 202752
Total No. of Host in a Network = 256-2 = 254
Total No. of Computers = 202752×254 = 532676608

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